msin616 final project
1.0.0
Este é um banco de dados simples que pode ser usado para manter os dados armazenados e processados por uma biblioteca de empréstimo . O banco de dados foi projetado modificando o banco de dados Pubs da Microsoft. A base de dados Pubs fornece um conjunto de informações fictícias sobre editoras , autores , títulos e vendas de livros. Agora é considerado obsoleto ; não é mais fornecido com SQL Server desde a versão 2008 . As tabelas e campos são bastante óbvios. Eles possuem nomes como Authors , Titles , etc., que refletem seu conteúdo. E os campos também têm nomes óbvios que explicam o que contêm.
Você pode encontrar os detalhes sobre o Pubs DB original no link: Microsoft Pubs DB
Abaixo você pode ver o diagrama de banco de dados alterado do banco de dados Pubs
Link para o esquema do banco de dados: DB Schema
Microsoft SQL Server 2019 - 15.0.4198.2 Developer Edition (64 bits) no Linux (Ubuntu 20.04.3 LTS)Azure Data Studio versão 1.35.1Docker versão 4.4.2 (73305) Gentellela , um painel de administração de código aberto, foi usado para criar UI front-end. [TITLES] foi alterada e a coluna prequel_id foi adicionada para armazenar a prequela de um livro. [TITLES] . [TITLES] foi alterada e a coluna ISBN foi adicionada. [TITLES] . [Audit].[Book] para manter o histórico de auditoria dos livros criados. [Adventureworks].[Person].[Person] e [AdventureWorks].[HumanResources].[Employee] para gerar dados fictícios. Jobs foi eliminada Roysched foi descartada Employees foi alterada Employee_type foi criada Category foi criada TitleCategory foi criada Degrees foi criada Schools foi criada Branchs foi criada Shift_logs foi criada Paychecks foi criada Borrowers foi criada Bookcopies foi criada Bookcopy_history foi criada Books_borrowed foi criada 
Link para o módulo de interface do usuário front-end: Ver demonstração
Fluxograma do algoritmo da operação de criação de um livro
Procedimento armazenado para adicionar um livro à tabela TITLES
/*
Created by Nury Amanmadov
Date created: 10.04.2022
*/
CREATE PROCEDURE [dbo].[USP_InsertBook]
@book_title AS VARCHAR ( 100 )
,@prequel_id AS VARCHAR ( 6 ) = NULL
,@book_price AS MONEY
,@book_advance AS MONEY
,@book_royalty INT
,@book_ytd_sales INT
,@book_notes VARCHAR ( 800 )
,@book_pubdate DATETIME
,@book_isbn VARCHAR ( 17 )
,@pub_id AS CHAR ( 4 ) = NULL
,@pub_name AS VARCHAR ( 40 ) = NULL
,@pub_city AS VARCHAR ( 20 ) = NULL
,@pub_state AS CHAR ( 2 ) = NULL
,@pub_country AS VARCHAR ( 30 ) = NULL
,@author_id VARCHAR ( 11 ) = NULL
,@au_lname VARCHAR ( 40 ) = NULL
,@au_fname VARCHAR ( 20 ) = NULL
,@au_phone CHAR ( 12 ) = NULL
,@au_city VARCHAR ( 20 ) = NULL
,@au_state CHAR ( 2 ) = NULL
,@au_order TINYINT = 1
,@royalty_per INT = 100
AS
BEGIN
SET NOCOUNT ON ;
BEGIN TRY
BEGIN TRANSACTION
-- #region Insert into Publisher Table
IF (@pub_id IS NULL )
-- #region Create New Publisher
BEGIN
-- Create pub_id as Max Id + 1
SET @pub_id = ( SELECT CAST( MAX (CAST(pub_id AS INT ) + 1 ) AS VARCHAR ) FROM publishers AS VARCHAR )
INSERT INTO [pubs].[dbo].[publishers]
VALUES (
ISNULL(@pub_id, 1 )
,@pub_name
,@pub_city
,@pub_state
,@pub_country
)
-- #region Insert into Pub_Info Table
DECLARE @pr_info AS VARCHAR ( 255 )
SET @pr_info = (
SELECT ' This is sample text data for '
+ pub_name + ' , publisher '
+ pub_id + ' in the pubs database. '
+ pub_name + ' is located in ' + city + ' ' + country + ' . ' AS pr_info
FROM [pubs].[dbo].[publishers] p
WHERE p . pub_id = @pub_id
)
INSERT INTO [pubs].[dbo].[pub_info]
VALUES (
ISNULL(@pub_id, 1 )
, NULL
,@pr_info
)
-- #endregion
END
-- #endregion
ELSE
BEGIN
-- Just to make sure that selected publisher exists in the database
IF NOT EXISTS ( SELECT TOP 1 1 FROM publishers p WHERE pub_id = @pub_id)
BEGIN
;THROW 50001 , ' Publisher with selected ID does not exist ' , 1
END
ELSE
BEGIN
-- Setting params. Will be inserted into Audit.Book table
SELECT @pub_name = p . pub_name
,@pub_city = p . city
,@pub_state = p.[state]
,@pub_country = p . country
FROM publishers p
WHERE p . pub_id = @pub_id
END
END
-- #endregion
-- #region Insert into Titles Table
DECLARE @random_title_id [dbo].[tid] = [dbo].[fn_GenerateRandomTitleId](RAND())
INSERT INTO titles
VALUES
(
@random_title_id
,@book_title
,ISNULL(@pub_id, 1 )
,@book_price
,@book_advance
,@book_royalty
,@book_ytd_sales
,@book_notes
,@book_pubdate
,@prequel_id
,@book_isbn
)
-- #endregion
-- #region Insert into Authors Table
DECLARE @au_zip CHAR ( 5 )
DECLARE @au_contract BIT
DECLARE @au_address VARCHAR ( 40 )
IF(@author_id IS NULL )
BEGIN
-- Generate Random AuthorID
SET @author_id = dbo . fn_GenerateRandomAuthorId (RAND())
-- Setting Random Zip in the 99xyz format
SET @au_zip = ' 99 ' + ( SELECT (CAST((FLOOR(RAND() * ( 999 - 100 + 1 ) + 100 )) AS CHAR )))
-- Setting @au_contract as random
SET @au_contract = ( SELECT (CAST((FLOOR(RAND() * ( 1 - 0 + 1 ) + 0 )) AS BIT )))
-- Setting Random Address from AdventureWorks DB Person.Address table
SET @au_address = ( SELECT TOP 1 LEFT(AddressLine1, 40 ) FROM AdventureWorks . Person .Address WHERE AddressLine1 IS NOT NULL ORDER BY NEWID())
INSERT INTO authors
VALUES
(
@author_id
,@au_lname
,@au_fname
,@au_phone
,@au_address
,@au_city
,@au_state
,@au_zip
,@au_contract
)
END
ELSE
BEGIN
IF NOT EXISTS ( SELECT TOP 1 1 FROM authors a WHERE a . au_id = @author_id)
BEGIN
;THROW 50002 , ' Author with selected ID does not exist ' , 1
END
ELSE
BEGIN
SELECT @au_lname = a . au_lname
,@au_fname = a . au_fname
,@au_phone = a . phone
,@au_city = a . city
,@au_state = a.[state]
FROM authors a
WHERE a . au_id = @author_id
END
END
-- #endregion
-- #region Insert into TitleAuthor Table
INSERT INTO titleauthor
VALUES
(
@author_id
,@random_title_id
,@au_order
,@royalty_per
)
-- #endregion
-- #region Insert into Audit Table
INSERT INTO Audit . Book
VALUES
(
ISNULL(@pub_id, 1 )
,@pub_name
,@pub_city
,@pub_state
,@pub_country
,@random_title_id
,@prequel_id
,@book_title
, NULL
,@book_price
,@book_advance
,@book_royalty
,@book_ytd_sales
,@book_notes
,@book_pubdate
,@author_id
,@au_lname
,@au_fname
,@au_phone
,@au_address
,@au_city
,@au_state
,@au_zip
,@au_contract
,@royalty_per
,@au_order
,GETDATE()
, SYSTEM_USER
)
-- #endregion
PRINT( ' Book Has Been Sucessfully Added ' )
COMMIT TRANSACTION
END TRY
BEGIN CATCH
ROLLBACK TRANSACTION
PRINT( ' An Error Occured During The Transaction. Error SP: ' + ERROR_PROCEDURE() + ' Error line: ' + CAST(ERROR_LINE() AS VARCHAR ))
PRINT(ERROR_MESSAGE())
END CATCH
END O procedimento armazenado [dbo].[USP_InsertBook] é um pouco complexo porque não cria apenas um livro. Se não houver editora ou autor associado a esse novo livro, também ajuda o usuário a criá-los. É por isso que os parâmetros @pub_id e @author_id do procedimento armazenado [dbo].[USP_InsertBook] são opcionais. Se o usuário selecionar um editor ou autor existente no elemento do menu suspenso no aplicativo front-end, o valor selecionado da opção selecionada, na forma de @pub_id ou @author_id , será passado para o procedimento armazenado. Se um autor ou editor do novo livro não for encontrado no menu suspenso (ou banco de dados), um aplicativo facilita sua criação. Usando as últimas opções Create New Author... e Create New Publisher... no menu suspenso, um usuário pode criar um novo autor ou editor. Além disso, um livro pode ter prequela ou não. Considerando tudo isso, existem 4 cenários possíveis para a criação de um livro.
Nota: Os itens do menu suspenso são preenchidos com os autores e editores existentes em um banco de dados.
Esses casos de teste são:
+ Create Book for Existing Author and Existing Publisher
+ Create Book for Existing Author and Non-Existent Publisher
+ Create Book for Non-Existent Author and Existing Publisher
+ Create Book for Non-Existent Author and Non-Existent Publisher
Caso de teste 1: Criar livro para autor e editor existente
-- Publisher Allen & Unwin with pub_id = '9910' and Author J.R.R Tolkien with author_id = '254-26-6712' already exists on the db
EXEC pubs . dbo .USP_InsertBook @author_id = ' 254-26-6712 '
,@pub_id = ' 9910 '
,@au_order = 1
,@royalty_per = 100
,@book_title = ' The Silmarillion '
,@book_type = ' Mythopoeia Fantasy '
,@book_price = 45
,@book_advance = 2500000
,@book_royalty = 40
,@book_ytd_sales = 50000000
,@book_pubdate = ' 1977-09-15 '
,@book_notes = ' The Silmarillion is a collection of mythopoeic stories by the English writer J. R. R. Tolkien. 'Caso de teste 4: Criar livro para autor inexistente e editora inexistente
EXEC pubs . dbo .USP_InsertBook @pub_name = ' Crown Publishing Group '
,@pub_city = ' New York City '
,@pub_state = ' NY '
,@pub_country = ' US '
,@au_lname = ' Acemoglu '
,@au_fname = ' Daron '
,@au_phone = ' 999 000-0000 '
,@au_city = ' Newton '
,@au_state = ' MA '
,@au_order = 1
,@royalty_per = 50
,@book_title = ' Why Nations Fail '
,@book_type = ' Comparative Politics, Economics '
,@book_price = 70
,@book_advance = 100000
,@book_royalty = 30
,@book_ytd_sales = 500000
,@book_pubdate = ' 2012-03-20 '
,@book_notes = ' Why Nations Fail first published in 2012, is a book by economists Daron Acemoglu and James Robinson... 'Caso de teste 2: Criar livro para autor existente e editora inexistente
-- A book by existing author Daron Acemoglu with author_id = '408-40-8965' but with different publisher
EXEC pubs . dbo .USP_InsertBook @pub_name = ' Cambridge University Press '
,@pub_city = ' Cambridge '
,@pub_country = ' UK '
,@author_id = ' 408-40-8965 '
,@au_order = 1
,@royalty_per = 50
,@book_title = ' Economic Origins of Dictatorship and Democracy '
,@book_type = ' Economics, Macroeconomics '
,@book_price = 30
,@book_advance = 50000
,@book_royalty = 15
,@book_ytd_sales = 500000
,@book_pubdate = ' 2012-09-01 '
,@book_notes = ' Book develops a framework for analyzing the creation and consolidation of democracy... '
Caso de teste 3: Criar livro para autor inexistente e editora existente
-- Different book by existing 'Cambridge University Press' with pub_id = '9912'
EXEC pubs . dbo .USP_InsertBook @pub_id = ' 9912 '
,@au_lname = ' Von Zur Gathen '
,@au_fname = ' Joachim '
,@au_phone = ' 000 000-0000 '
,@au_city = ' Bonn '
,@au_order = 1
,@royalty_per = 50
,@book_title = ' Modern Computer Algebra '
,@book_type = ' Computer Science '
,@book_price = 100
,@book_advance = 50000
,@book_royalty = 10
,@book_ytd_sales = 10000
,@book_pubdate = ' 2013-01-01 '
,@book_notes = ' Computer algebra systems are now ubiquitous in all areas of science and engineering... '
Link para o módulo de interface do usuário front-end: Ver demonstração
Procedimento armazenado para adicionar um autor à tabela Authors
/*
Created by Nury Amanmadov
Date created: 17.04.2022
*/
CREATE PROCEDURE [dbo].[USP_CreateAuthor]
@au_lname VARCHAR ( 40 )
,@au_fname VARCHAR ( 20 )
,@au_phone CHAR ( 12 ) = ' 000 000-0000 '
,@au_address VARCHAR ( 250 ) = NULL
,@au_city VARCHAR ( 20 ) = NULL
,@au_state CHAR ( 2 ) = NULL
,@au_zip CHAR ( 5 ) = NULL
,@au_contract BIT = 0
AS
BEGIN
BEGIN TRY
-- Generate Random AuthorID
DECLARE @au_id dbo . tid
SET @au_id = dbo . fn_GenerateRandomAuthorId (RAND())
INSERT INTO authors
VALUES
(
@au_id
,@au_lname
,@au_fname
,@au_phone
,@au_address
,@au_city
,@au_state
,@au_zip
,@au_contract
)
END TRY
BEGIN CATCH
PRINT( ' An Error Occured During The Transaction. Error SP: ' + ERROR_PROCEDURE() + ' Error line: ' + CAST(ERROR_LINE() AS VARCHAR ))
PRINT(ERROR_MESSAGE())
END CATCH
END Como a criação de um author_id é usada em vários procedimentos armazenados, criei uma função que cria author_id .
CREATE FUNCTION [dbo].[fn_GenerateRandomAuthorId](
@RAND FLOAT
)
RETURNS VARCHAR ( 11 ) AS
BEGIN
DECLARE @author_id VARCHAR ( 11 )
DECLARE @isFound BIT = 0
WHILE (@isFound = 0 )
BEGIN
DECLARE @a1 AS CHAR ( 3 ) = ( SELECT (CAST((FLOOR(@RAND * ( 999 - 100 + 1 ) + 100 )) AS CHAR )))
DECLARE @a2 AS CHAR ( 2 ) = ( SELECT (CAST((FLOOR(@RAND * ( 99 - 10 + 1 ) + 10 )) AS CHAR )))
DECLARE @a3 AS CHAR ( 4 ) = ( SELECT (CAST((FLOOR(@RAND * ( 9999 - 1000 + 1 ) + 1000 )) AS CHAR )))
SET @author_id = ( SELECT @a1 + ' - ' + @a2 + ' - ' + @a3)
IF EXISTS( SELECT TOP 1 1 FROM [authors] WHERE au_id = @author_id)
BEGIN
CONTINUE
END
ELSE
BEGIN
SET @isFound = 1
END
END
RETURN @author_id
END;
Link para o módulo de interface do usuário front-end: Ver demonstração
Procedimento armazenado para adicionar um CoAuthor . Se o coautor não existir no menu suspenso, podemos criar um novo autor e adicioná-lo.
-- for demonstration purposes some columns (like address) are generated with dummy data
CREATE PROCEDURE USP_InsertCoAuthorForTitle
@title_id dbo . tid
,@au_id VARCHAR ( 11 ) = NULL
,@au_lname VARCHAR ( 40 ) = NULL
,@au_fname VARCHAR ( 20 ) = NULL
,@au_phone CHAR ( 12 ) = ' 000-000-0000 '
,@au_city VARCHAR ( 20 ) = NULL
,@au_state CHAR ( 2 ) = NULL
,@au_order TINYINT = 2
,@royalty_per INT = 0
AS
BEGIN
BEGIN TRY
BEGIN TRANSACTION
IF NOT EXISTS( SELECT TOP 1 1 FROM titles WHERE title_id = @title_id)
BEGIN
;THROW 50001 , ' Book with provided ID does not exist ' , 1
END
IF(@au_id IS NULL )
BEGIN
DECLARE @au_zip CHAR ( 5 )
DECLARE @au_contract BIT
DECLARE @au_address VARCHAR ( 40 )
-- Generate Random AuthorID
SET @au_id = dbo . fn_GenerateRandomAuthorId (RAND())
-- Setting Random Zip in the 99xyz format
SET @au_zip = ' 99 ' + ( SELECT (CAST((FLOOR(RAND() * ( 999 - 100 + 1 ) + 100 )) AS CHAR )))
-- Setting @au_contract as random
SET @au_contract = ( SELECT (CAST((FLOOR(RAND() * ( 1 - 0 + 1 ) + 0 )) AS BIT )))
-- Setting Random Address from AdventureWorks DB Person.Address table
SET @au_address = (
SELECT TOP 1 LEFT(AddressLine1, 40 )
FROM AdventureWorks . Person .Address
WHERE AddressLine1 IS NOT NULL
ORDER BY NEWID()
)
INSERT INTO authors
VALUES
(
@au_id
,@au_lname
,@au_fname
,@au_phone
,@au_address
,@au_city
,@au_state
,@au_zip
,@au_contract
)
INSERT INTO titleauthor
VALUES
(
@au_id
,@title_id
,@au_order
,@royalty_per
)
END
ELSE
BEGIN
IF NOT EXISTS( SELECT TOP 1 1 FROM authors WHERE au_id = @au_id)
BEGIN
;THROW 50002 , ' Author with provided ID does not exist ' , 1
END
ELSE
BEGIN
INSERT INTO titleauthor
VALUES
(
@au_id
,@title_id
,@au_order
,@royalty_per
)
END
END
PRINT( ' CoAuthor for the Provided Book Has Been Sucessfully Added ' )
COMMIT TRANSACTION
END TRY
BEGIN CATCH
ROLLBACK TRANSACTION
PRINT( ' An Error Occured During The Transaction. Error SP: ' + ERROR_PROCEDURE() + ' Error line: ' + CAST(ERROR_LINE() AS VARCHAR ))
PRINT(ERROR_MESSAGE())
END CATCH
END
Link para o módulo de interface do usuário front-end: Ver demonstração
Procedimento armazenado para adicionar um funcionário à tabela Employee
/*
Created by Nury Amanmadov
Date created: 11.04.2022
*/
CREATE PROCEDURE [dbo].[USP_CreateEmployee]
(
@firstname AS VARCHAR ( 100 )
,@lastname AS VARCHAR ( 100 )
,@address AS VARCHAR ( 200 )
,@homephone AS CHAR ( 12 )
,@cellphone AS CHAR ( 12 )
,@salary_type AS CHAR ( 1 )
,@salary AS DECIMAL ( 6 , 0 )
,@birthdate DATE
,@degee_id INT
,@school_id INT
,@branch_id INT
,@ishead_librarin BIT
,@emp_type_id INT
,@degreedate DATE
)
AS
BEGIN
SET NOCOUNT ON ;
BEGIN TRY
BEGIN TRANSACTION
DECLARE @id INT = ( SELECT MAX (employee_id) + 1 FROM employees)
INSERT INTO [pubs].[dbo].[employees]
VALUES (
@id
,@firstname
,@lastname
,@address
,@homephone
,@cellphone
,@salary_type
,@salary
,@birthdate
,GETDATE()
, 114
,@degee_id
,@school_id
,@branch_id
,@ishead_librarin
,@emp_type_id
,@degreedate
, 1
)
-- #endregion
PRINT( ' Employee Has Been Sucessfully Added ' )
COMMIT TRANSACTION
END TRY
BEGIN CATCH
ROLLBACK TRANSACTION
PRINT( ' An Error Occured During The Transaction. Error SP: ' + ERROR_PROCEDURE() + ' Error line: ' + CAST(ERROR_LINE() AS VARCHAR ))
PRINT(ERROR_MESSAGE())
END CATCH
END 
Link para o módulo de interface do usuário front-end: Ver demonstração
Procedimento armazenado para obter books na forma de HTML table row
/*
Created by Nury Amanmadov
Date created: 16.04.2022 ddMMyyyy
Selects TOP 20 Book as in the form of HTML table row records
These records then rendered as an HTML elements on the front-end side
*/
CREATE PROCEDURE [dbo].[USP_GetAllBooks]
AS
BEGIN
SELECT TOP 20
' <tr class="even pointer">
<td class="a-center "><input type="checkbox" class="flat" name="table_records"></td>
<td> ' + t . title_id + ' </td>
<td> ' + title + ' </td>
<td> ' + a . au_fname + ' ' + a . au_lname + ' </td>
<td> ' + p . pub_name + ' </td>
<td> ' + type + ' </td>
<td> ' + ISNULL(CAST(price AS VARCHAR ), ' NA ' ) + ' </td>
<td> ' + ISNULL(CAST(advance AS VARCHAR ), ' NA ' ) + ' </td>
<td> ' + ISNULL(CAST(royalty AS VARCHAR ), ' NA ' ) + ' </td>
<td> ' + ISNULL(CAST(ytd_sales AS VARCHAR ), ' NA ' ) + ' </td>
<td class="last"><a href="#">View</a></td>
</tr> ' AS TableRow
FROM titles t
JOIN publishers p ON t . pub_id = p . pub_id
JOIN titleauthor ta ON ta . title_id = t . title_id
JOIN authors a ON a . au_id = ta . au_id
ORDER BY p . pub_id DESC
END
Link para o módulo de interface do usuário front-end: Ver demonstração
Procedimento armazenado para obter authors na forma de HTML table row
CREATE PROCEDURE [dbo].[USP_GetAllAuthors]
AS
BEGIN
SELECT TOP 20
' <tr class="even pointer">
<td class="a-center "><input type="checkbox" class="flat" name="table_records"></td>
<td> ' + au_id + ' </td>
<td> ' + au_fname + ' </td>
<td> ' + au_lname + ' </td>
<td> ' + ISNULL(CAST(phone AS VARCHAR ), ' NA ' ) + ' </td>
<td> ' + ISNULL(CAST(address AS VARCHAR ), ' NA ' ) + ' </td>
<td> ' + ISNULL(CAST(city AS VARCHAR ), ' NA ' ) + ' </td>
<td> ' + ISNULL(CAST(state AS VARCHAR ), ' NA ' ) + ' </td>
<td> ' + ISNULL(CAST(zip AS VARCHAR ), ' NA ' ) + ' </td>
<td> ' + ISNULL(CAST(contract AS VARCHAR ), ' NA ' ) + ' </td>
<td class="last"><a href="#">View</a></td>
</tr> ' AS TableRow
FROM authors a
ORDER BY zip DESC
END
Link para o módulo de interface do usuário front-end: Ver demonstração
Procedimento armazenado para obter publishers na forma de HTML table row
CREATE PROCEDURE [dbo].[USP_GetAllPublishers]
AS
BEGIN
SELECT TOP 20
' <tr class="even pointer">
<td class="a-center "><input type="checkbox" class="flat" name="table_records"></td>
<td> ' + p . pub_id + ' </td>
<td> ' + p . pub_name + ' </td>
<td> ' + p . city + ' </td>
<td> ' + ISNULL(p.[state], ' NA ' ) + ' </td>
<td> ' + p . country + ' </td>
<td> ' + CAST( COUNT (DISTINCT t . title_id ) AS VARCHAR ) + ' </td>
<td> ' + CAST(ISNULL( SUM ( t . ytd_sales ), 0 ) AS VARCHAR ) + ' </td>
<td> ' + CAST( COUNT (DISTINCT e . emp_id ) AS VARCHAR ) + ' </td>
<td class="last"><a href="#">View</a></td>
</tr> ' AS TableRow
FROM publishers p
LEFT JOIN titles t ON t . pub_id = p . pub_id
LEFT JOIN employee e ON e . pub_id = p . pub_id
GROUP BY p . pub_id
, p . pub_name
, p . city
,p.[state]
, p . country
ORDER BY SUM ( t . ytd_sales ) DESC
END
Link para o módulo de interface do usuário front-end: Ver demonstração
Aqui no front-end, desenvolvi alguma lógica com javascript para simular a funcionalidade do procedimento armazenado. Este é um procedimento armazenado Recursive para obter livros anteriores ou livros de um livro específico de uma série. CTE usado dentro da consulta.
/*
Created by Nury Amanmadov
Date created: 17.04.2022 ddMMyyyy
Selects all the prequel book series of a given book
*/
CREATE PROCEDURE [dbo].[USP_GetAllPrequelBooksByTitleId]
@title_id dbo . tid
AS
BEGIN
IF NOT EXISTS( SELECT TOP 1 1 FROM titles WHERE title_id = @title_id)
BEGIN
;THROW 50001 , ' Book with provided ID does not exist ' , 1
END
;WITH CTEBooks
AS
(
SELECT title_id AS TitleId
,title AS Book
,prequel_id
,CAST( t1 . pubdate AS DATE ) AS [Publication Date ]
, p . pub_name AS Publisher
FROM titles t1
JOIN publishers p ON p . pub_id = t1 . pub_id
WHERE title_id = @title_id
UNION ALL
SELECT t2 . title_id AS TitleId
, t2 . title AS Book
, t2 . prequel_id
,CAST( t2 . pubdate AS DATE ) AS [Publication Date ]
, p . pub_name AS Publisher
FROM titles t2
JOIN publishers p ON p . pub_id = t2 . pub_id
JOIN CTEBooks ON t2 . title_id = CTEBooks . prequel_id
)
SELECT CTEBooks . TitleId
, CTEBooks . Book
,ISNULL( t . title , ' No Prequel ' ) AS PrequelBook
,[Publication Date ]
, a . au_fname + ' ' + a . au_lname AS Author
, CTEBooks . Publisher
FROM CTEBooks
LEFT JOIN titles t ON CTEBooks . prequel_id = t . title_id
LEFT JOIN titleauthor ta ON ta . title_id = CTEBooks . TitleId
LEFT JOIN authors a ON a . au_id = ta . au_id
END Agora, se executarmos este procedimento armazenado com um title_id de um livro contínuo de uma série, obteremos os livros anteriores desse livro.
-- For 'Harry Potter and the Deathly Hallows' in the 'Harry Potter' Series
EXEC USP_GetAllPrequelBooksByTitleId @title_id = ' GU4539 ' 
-- For 'The Return of the King' in the 'Lord of the Rings' Series
EXEC USP_GetAllPrequelBooksByTitleId @title_id = ' ZJ4675 ' 
-- For 'A Dream of Spring' in the 'Game of the Thrones' Series
EXEC USP_GetAllPrequelBooksByTitleId @title_id = ' SA4547 ' 
/*
Created by Nury Amanmadov
Date created: 18.04.2022 ddMMyyyy
Selects all the continuing books in series
*/
CREATE PROCEDURE [dbo].[USP_GetAllContinuingBooksByTitleId]
@title_id dbo . tid
AS
BEGIN
IF NOT EXISTS( SELECT TOP 1 1 FROM titles WHERE title_id = @title_id)
BEGIN
;THROW 50001 , ' Book with provided ID does not exist ' , 1
END
;WITH CTEBooks
AS
(
SELECT title_id AS TitleId
,title AS Book
,prequel_id
,CAST( t1 . pubdate AS DATE ) AS [Publication Date ]
, p . pub_name AS Publisher
,[Order In Series] = 1
FROM titles t1
JOIN publishers p ON p . pub_id = t1 . pub_id
WHERE title_id = @title_id
UNION ALL
SELECT t2 . title_id AS TitleId
, t2 . title AS Book
, t2 . prequel_id
,CAST( t2 . pubdate AS DATE ) AS [Publication Date ]
, p . pub_name AS Publisher
,[Order In Series] + 1
FROM titles t2
JOIN publishers p ON p . pub_id = t2 . pub_id
JOIN CTEBooks ON t2 . prequel_id = CTEBooks . TitleId
)
SELECT CTEBooks . TitleId
, CTEBooks . Book
,ISNULL( t . title , ' No Prequel ' ) AS PrequelBook
,[Publication Date ]
, a . au_fname + ' ' + a . au_lname AS Author
, CTEBooks . Publisher
,[Order In Series]
FROM CTEBooks
LEFT JOIN titles t ON CTEBooks . prequel_id = t . title_id
LEFT JOIN titleauthor ta ON ta . title_id = CTEBooks . TitleId
LEFT JOIN authors a ON a . au_id = ta . au_id
END Agora, se executarmos este procedimento armazenado com um title_id de um livro de uma série, obteremos os livros contínuos dessa série.
-- For 'The Lord of the Rings' Series
EXEC [dbo].[USP_GetAllContinuingBooksByTitleId] ' EX5727 ' 
-- For 'A Game of Thrones' Series
EXEC [dbo].[USP_GetAllContinuingBooksByTitleId] ' CI5668 ' 
-- For 'Harry Potter' Series
EXEC [dbo].[USP_GetAllContinuingBooksByTitleId] ' VC5136 ' 
Procedimento armazenado para excluir um livro
/*
Created by Nury Amanmadov
Date created: 16.04.2022
Rule for deleting a book
- Publisher related to that title will not be deleted
- PublisherInfo related to the Publisher of that title will not be deleted
- Author related to that title will not be deleted
- Records related to that title from Titles and TitleAuthor tables will be deleted
Because there are publishers without any title on the initial database created by Microsoft (ex: pub_id with 1622 and 1756)
SELECT DISTINCT pub_id
FROM publishers
WHERE pub_id NOT IN
(
SELECT DISTINCT pub_id FROM titles
)
*/
CREATE PROCEDURE [dbo].[USP_DeleteBook]
@title_id dbo . tid ,
@au_id dbo . id
AS
BEGIN
BEGIN TRY
BEGIN TRANSACTION
DELETE FROM titles WHERE title_id = @title_id
DELETE FROM titleauthor WHERE title_id = @title_id and au_id = @au_id
PRINT( ' Book Has Been Sucessfully Deleted ' )
COMMIT TRANSACTION
END TRY
BEGIN CATCH
ROLLBACK TRANSACTION
PRINT( ' An Error Occured During The Transaction. Error SP: ' + ERROR_PROCEDURE() + ' Error line: ' + CAST(ERROR_LINE() AS VARCHAR ))
PRINT(ERROR_MESSAGE())
END CATCH
END SELECT *
FROM [pubs].[Audit].[Book]Link para o arquivo de registros [Auditoria].[Livro]: Ver Registros
A biblioteca emite cartões de biblioteca para pessoas que desejam emprestar livros da biblioteca. A biblioteca mantém uma lista de cada mutuário, armazenando a card id , borrower name , address , phone number , birthdate , date the card was issued e balance due . Um cartão expira dez anos a partir da data de sua emissão. Se a pessoa tiver menos de 18 anos , a biblioteca também manterá informações sobre os pais ou responsável legal do Mutuário, como name , address e phone number . Uma pessoa pode ter apenas um cartão de biblioteca válido por vez. Uma pessoa não pode receber um novo cartão de biblioteca se estiver devendo dinheiro de um cartão vencido .
/*
Rules for creating a card for borrower
- A person can have only one valid library card at a given time.
- A person can’t be issued a new library card, if he owes money on an expired card.
- a person can not be younger than 10.
*/
CREATE PROCEDURE [dbo].[USP_CreateBorrower]
@ssn VARCHAR ( 11 )
,@fname VARCHAR ( 100 )
,@lname VARCHAR ( 100 )
,@address VARCHAR ( 200 )
,@phone CHAR ( 12 )
,@birthdate DATE
,@lg_address VARCHAR ( 200 ) = NULL
,@lg_name VARCHAR ( 100 ) = NULL
,@lg_phone VARCHAR ( 12 ) = NULL
AS
BEGIN
BEGIN TRY
-- Check if borrower has an active card
IF EXISTS ( SELECT TOP 1 1 FROM borrowers WHERE ssn = @ssn AND isexpired = 0 )
BEGIN
;THROW 50001 , ' A person already has an active card. ' , 1
END
-- Check if borrower has an a balancedue on expired card
IF EXISTS ( SELECT TOP 1 1 FROM borrowers WHERE ssn = @ssn AND isexpired = 1 AND balancedue > 0 )
BEGIN
;THROW 50002 , ' A person owes library from previous card. ' , 1
END
-- Check if borrower is older than 10
DECLARE @age INT = DATEDIFF(YY,@birthdate,GETDATE())
IF(@age < 10 )
BEGIN
;THROW 50003 , ' Borrower can not be younger than 10. ' , 1
END
DECLARE @id INT = ( SELECT MAX (id) + 1 FROM borrowers)
DECLARE @cardid INT = ( SELECT MAX (card_id) + 1 FROM borrowers)
-- validation of legal guardian details should be on the front-end
INSERT INTO borrowers
VALUES
(
ISNULL(@id, 1 ) -- if first time
,ISNULL(@cardid, 1 ) -- if first time
,@ssn
,@fname
,@lname
,@address
,@phone
,@birthdate
,GETDATE()
, 0 -- initial balance
, 0 -- default value
,@lg_address
,@lg_name
,@lg_phone
)
END TRY
BEGIN CATCH
PRINT( ' An Error Occured During The Transaction. Error SP: ' + ERROR_PROCEDURE() + ' Error line: ' + CAST(ERROR_LINE() AS VARCHAR ))
PRINT(ERROR_MESSAGE())
END CATCH
ENDProcedimento armazenado para cartões com vencimento após 10 anos
CREATE PROCEDURE [dbo].[USP_ExpireLibraryCards]
AS
BEGIN
UPDATE borrowers SET isexpired = 1
WHERE DATEDIFF(YY,card_issuedate,GETDATE()) >= 10
ENDDados fictícios do mutuário criados usando o procedimento armazenado abaixo.
CREATE PROCEDURE [dbo].[USP_InsertRandomBorrower]
AS
BEGIN
DECLARE @id INT
DECLARE @ssn VARCHAR ( 11 )
DECLARE @fname VARCHAR ( 100 )
DECLARE @lname VARCHAR ( 100 )
DECLARE @address VARCHAR ( 200 )
DECLARE @phone CHAR ( 12 )
DECLARE @birthdate DATE
DECLARE @cardissuedate DATE
DECLARE @balancedue DECIMAL ( 6 , 2 )
DECLARE @lgname VARCHAR ( 200 ) = NULL
DECLARE @lgaddress VARCHAR ( 200 ) = NULL
DECLARE @lgphone VARCHAR ( 200 ) = NULL
SET @id = ( SELECT MAX (id) + 1 FROM borrowers )
SET @fname = dbo . fn_GenerateFirstName ()
SET @lname = dbo . fn_GenerateLastName ()
SET @ssn = dbo . fn_GenerateRandomSsn (RAND())
SET @address = dbo . fn_GenerateRandomAddress ()
SET @phone = dbo . fn_GenerateRandomPhone (RAND())
SET @birthdate = dbo . fn_GenerateRandomDate ( ' 1999-01-01 ' , ' 2010-01-01 ' ,RAND())
DECLARE @age INT = DATEDIFF(YY,@birthdate,GETDATE())
SET @cardissuedate = DATEADD(year, dbo . fn_GetRandomNumber ( 5 ,@age,RAND()), @birthdate)
SET @balancedue = 0
IF(@age < 17 )
BEGIN
SET @lgname = dbo . fn_GenerateFirstName ()
-- Set randomly address of borrower same as guardians
DECLARE @isSameAddress BIT = CAST(ROUND(RAND(), 0 ) AS BIT )
IF(@isSameAddress = 0 )
BEGIN
SET @lgaddress = @address
END
ELSE
BEGIN
SET @lgaddress = dbo . fn_GenerateRandomAddress ()
END
SET @lgphone = dbo . fn_GenerateRandomPhone (RAND())
END
INSERT INTO borrowers
VALUES
(
ISNULL(@id, 1 ) -- if first time
,ISNULL(@id, 1 ) -- if first time
,@ssn
,@fname
,@lname
,@address
,@phone
,@birthdate
,@cardissuedate
,@balancedue
, 0 -- default value
,@lgaddress
,@lgname
,@lgphone
)
PRINT( ' Borrower sucessfully created. ' )
ENDFunções definidas pelo usuário para criar dados fictícios necessários
-- Since inside user defined functions we cant use NEWID() or RAND()
CREATE View [dbo].[view_NewID] AS SELECT NEWID() AS idCREATE FUNCTION [dbo].[fn_GenerateFirstName]()
RETURNS VARCHAR ( 100 ) AS
BEGIN
DECLARE @fname VARCHAR ( 100 )
SET @fname =
(
SELECT TOP 1 p . FirstName
FROM AdventureWorks . Person .Person p
ORDER BY ( SELECT id FROM dbo . view_NewID )
)
RETURN @fname
END;CREATE FUNCTION [dbo].[fn_GenerateLastName]()
RETURNS VARCHAR ( 100 ) AS
BEGIN
DECLARE @lname VARCHAR ( 100 )
SET @lname =
(
SELECT TOP 1 p . LastName
FROM AdventureWorks . Person .Person p
ORDER BY ( SELECT id FROM dbo . view_NewID )
)
RETURN @lname
END;CREATE FUNCTION [dbo].[fn_GenerateRandomAddress]()
RETURNS VARCHAR ( 200 ) AS
BEGIN
DECLARE @address VARCHAR ( 200 )
SET @address =
(
SELECT TOP 1 ad . AddressLine1
FROM AdventureWorks . Person .Address ad
WHERE AddressLine1 IS NOT NULL
ORDER BY ( SELECT id FROM dbo . view_NewID )
)
RETURN @address
END;CREATE FUNCTION [dbo].[fn_GenerateRandomDate]
(
@DateStart DATE
,@DateEnd DATE
,@RAND FLOAT
)
RETURNS DATE AS
BEGIN
DECLARE @randomDate DATE
SET @randomDate = DateAdd(Day, @RAND * DateDiff(Day, @DateStart, @DateEnd), @DateStart)
RETURN @randomDate
END;CREATE FUNCTION [dbo].[fn_GenerateRandomPhone]
(
@RAND FLOAT
)
RETURNS VARCHAR ( 12 ) AS
BEGIN
DECLARE @phone VARCHAR ( 12 )
DECLARE @p1 AS CHAR ( 3 ) = ( SELECT (CAST((FLOOR(@RAND * ( 999 - 100 + 1 ) + 100 )) AS CHAR )))
DECLARE @p2 AS CHAR ( 3 ) = ( SELECT (CAST((FLOOR(@RAND * ( 999 - 100 + 1 ) + 100 )) AS CHAR )))
DECLARE @p3 AS CHAR ( 4 ) = ( SELECT (CAST((FLOOR(@RAND * ( 9999 - 1000 + 1 ) + 1000 )) AS CHAR )))
SET @phone = ( SELECT @p1 + ' - ' + @p2 + ' - ' + @p3)
RETURN @phone
END;CREATE FUNCTION [dbo].[fn_GenerateRandomSsn]
(
@RAND FLOAT
)
RETURNS VARCHAR ( 11 ) AS
BEGIN
DECLARE @ssn VARCHAR ( 11 )
SET @ssn = (
CAST(CAST( 100 + ( 898 * @RAND) AS INT ) AS VARCHAR ( 3 )) +
' - ' +
CAST(CAST( 10 + ( 88 * @RAND) AS INT ) AS VARCHAR ( 2 )) +
' - ' +
CAST(CAST( 1000 + ( 8998 * @RAND) AS INT ) AS VARCHAR ( 4 ))
)
RETURN @ssn
END;CREATE FUNCTION [dbo].[fn_GenerateRandomTitleId](
@RAND FLOAT
)
RETURNS [dbo].[tid] AS
BEGIN
DECLARE @random_title_id [dbo].[tid]
DECLARE @isFound BIT = 0
WHILE (@isFound = 0 )
BEGIN
DECLARE @randomid1 UNIQUEIDENTIFIER = ( SELECT id FROM dbo . view_NewID )
DECLARE @randomid2 UNIQUEIDENTIFIER = ( SELECT id FROM dbo . view_NewID )
DECLARE @t1 AS CHAR ( 1 ) = ( SELECT SUBSTRING ( ' ABCDEFGHIJKLMNOPQRSTUVWXYZ ' ,(ABS(CHECKSUM(@randomid1)) % 26 ) + 1 , 1 ))
DECLARE @t2 AS CHAR ( 1 ) = ( SELECT SUBSTRING ( ' ABCDEFGHIJKLMNOPQRSTUVWXYZ ' ,(ABS(CHECKSUM(@randomid2)) % 26 ) + 1 , 1 ))
DECLARE @t3 AS CHAR ( 1 ) = ( SELECT (CAST((FLOOR(@RAND * ( 9 - 1 + 1 ) + 1 )) AS CHAR )))
DECLARE @t4 AS CHAR ( 1 ) = ( SELECT (CAST((FLOOR(@RAND * ( 9 - 1 + 1 ) + 1 )) AS CHAR )))
DECLARE @t5 AS CHAR ( 1 ) = ( SELECT (CAST((FLOOR(@RAND * ( 9 - 1 + 1 ) + 1 )) AS CHAR )))
DECLARE @t6 AS CHAR ( 1 ) = ( SELECT (CAST((FLOOR(@RAND * ( 9 - 1 + 1 ) + 1 )) AS CHAR )))
SET @random_title_id = ( SELECT @t1 + @t2 + @t3 + @t4 + @t5 + @t6)
IF EXISTS( SELECT TOP 1 1 FROM [titles] WHERE title_id = @random_title_id)
BEGIN
CONTINUE
END
ELSE
BEGIN
SET @isFound = 1
END
END
RETURN @random_title_id
END; Para cada exemplar de livro emprestado, a biblioteca registra a copy id e o card number da pessoa que o emprestou. A biblioteca mantém registro da date on which it was borrowed e registra a data de vencimento que é duas semanas após a data do empréstimo. Quando a cópia é devolvida este registro é atualizado com a return date . Quando um exemplar de livro é emprestado, o exemplar é marcado como BORROWED . Quando a cópia do livro é devolvida, a cópia é marcada como AVAILABLE ou NOT BORROWED . Um mutuário não pode emprestar um livro de uma agência específica, a menos que essa agência tenha uma cópia desse livro e ele esteja atualmente em estoque (por exemplo, não sendo emprestado por outra pessoa). Quando um mutuário devolve uma cópia do livro após a data de vencimento, o sistema calcula o amount owed e quaisquer cobranças vencidas incorridas são adicionados ao card balance . Um mutuário não pode usar um cartão para emprestar livros se dever mais de 10 dólares nesse cartão. A biblioteca possui uma lista de cobranças vencidas. As cobranças são atualmente de 0,05 por dia para livros juvenis e de 0,10 por dia para livros para adultos. Quando um livro é devolvido com atraso, o mutuário paga encargos em vigor no momento da devolução do livro. Qualquer item de leitura classificado como reference não poderá ser emprestado.
Procedimento armazenado para operação de empréstimo
/*
Rules for borrowing a book:
- Any reading item that is categorized as reference may not be borrowed.
- Copies that are in POOR condition may not be borrowed.
- When a book copy is borrowed, the copy is marked as BORROWED. BORROWED copies may not be borrowed.
- A borrower can not use a card to borrow books, if he owes more than 10 dollars on that card.
*/
CREATE PROCEDURE [dbo].[USP_BorrowBook]
@copy_id AS INT ,
@card_id AS INT
AS
BEGIN
SET NOCOUNT ON ;
BEGIN TRY
BEGIN TRANSACTION
-- #region Check if copy is of type Reference
IF EXISTS(
SELECT TOP 1 1
FROM titlecategory tc
JOIN bookcopies bc ON bc . title_id = tc . title_id
WHERE bc . copy_id = @copy_id AND tc . title_type_id = ( SELECT type_id FROM category c WHERE c.[type] = ' Reference ' )
)
BEGIN
;THROW 50001 , ' Copy of type Reference can not be borrowed ' , 1
END
-- #endregion
-- #region Check if copy is in POOR
IF EXISTS (
SELECT copy_id
FROM bookcopies
WHERE condition = ' POOR ' AND copy_id = @copy_id
)
BEGIN
;THROW 50002 , ' Copies in POOR condition can not be borrowed ' , 1
END
-- #endregion
-- #region Check if copy is BORROWED or Discarded
IF EXISTS (
SELECT copy_id
FROM bookcopies
WHERE (isactive = 0 OR isavailable = 0 ) AND copy_id = @copy_id
)
BEGIN
;THROW 50003 , ' Copies that are Discarded or already Borrowed can not be borrowed. ' , 1
END
-- #endregion
-- #region Check if borrower is available to borrow a book
IF EXISTS (
SELECT *
FROM borrowers
WHERE card_id = @card_id AND (isexpired = 1 OR balancedue >= 10 )
)
BEGIN
;THROW 50004 , ' Either borrowers card expired or borrower owes over 10 dollars. ' , 1
END
-- #endregion
UPDATE bookcopies SET isavailable = 0 WHERE copy_id = @copy_id
DECLARE @id INT = ( SELECT MAX (id) + 1 FROM books_borrowed)
INSERT INTO books_borrowed
VALUES
(
ISNULL(@id, 1 ),
@copy_id,
@card_id,
GETDATE(),
GETDATE() + 14 ,
0 ,
NULL
)
PRINT( ' Book Has Been Sucessfully Borrowed ' )
COMMIT TRANSACTION
END TRY
BEGIN CATCH
ROLLBACK TRANSACTION
PRINT( ' An Error Occured During The Transaction. Error SP: ' + ERROR_PROCEDURE() + ' Error line: ' + CAST(ERROR_LINE() AS VARCHAR ))
PRINT(ERROR_MESSAGE())
END CATCH
END Procedimento armazenado para operação de retorno
CREATE PROCEDURE [dbo].[USP_ReturnBook]
@card_id INT ,
@copy_id INT
AS
BEGIN
SET NOCOUNT ON ;
BEGIN TRY
BEGIN TRANSACTION
-- #region Check borrowed book exists
IF NOT EXISTS( SELECT TOP 1 1 FROM books_borrowed WHERE card_id = @card_id AND copy_id = @copy_id AND isReturned = 0 )
BEGIN
;THROW 50001 , ' There is no borrowed book with the given details. ' , 1
END
-- #endregion
DECLARE @id INT = ( SELECT id FROM books_borrowed WHERE card_id = @card_id AND copy_id = @copy_id AND isReturned = 0 )
DECLARE @daysElapsed INT = ( SELECT DATEDIFF(DD,borroweddate,GETDATE()) FROM books_borrowed WHERE id = @id)
-- PRINT(CAST(@daysElapsed as varchar))
-- Set book available to borrow
UPDATE bookcopies SET isavailable = 1 WHERE copy_id = @copy_id
-- Set isReturned to true
UPDATE books_borrowed SET isReturned = 1 , returndate = GETDATE() WHERE id = @id
DECLARE @pr DECIMAL ( 6 , 2 )
IF(@daysElapsed > 14 )
BEGIN
DECLARE @typeId INT = ( SELECT tc . title_type_id FROM bookcopies bc JOIN titlecategory tc ON tc . title_id = bc . title_id WHERE copy_id = @copy_id)
-- Check if Juvenile
IF(@typeId = 4 )
BEGIN
SET @pr = . 05
END
ELSE
BEGIN
SET @pr = . 10
END
-- Update card balancedue
UPDATE borrowers SET balancedue = balancedue + (@pr * @daysElapsed) WHERE card_id = @card_id
END
PRINT( ' Book Has Been Sucessfully Returned ' )
COMMIT TRANSACTION
END TRY
BEGIN CATCH
ROLLBACK TRANSACTION
PRINT( ' An Error Occured During The Transaction. Error SP: ' + ERROR_PROCEDURE() + ' Error line: ' + CAST(ERROR_LINE() AS VARCHAR ))
PRINT(ERROR_MESSAGE())
END CATCH
END Procedimento armazenado para listar todos os livros disponíveis para empréstimo
CREATE PROCEDURE [dbo].[USP_GetAllAvailableBooks]
AS
BEGIN
SELECT *
FROM bookcopies bc
JOIN titles t ON t . title_id = bc . title_id
JOIN titlecategory tc ON tc . title_id = bc . title_id
JOIN category c ON c . type_id = tc . title_type_id
WHERE bc . isactive = 1 AND isavailable = 1 AND c . type <> ' Reference '
END A Biblioteca atribui uma Condition a cada exemplar do livro. Os valores de condição de amostra podem ser NEW , EXCELLENT , GOOD , WORN e POOR . Eventualmente, as cópias que estiverem em POOR condições serão descartadas e substituídas por novas cópias. Um mutuário pode reconhecer que perdeu um exemplar de um livro. Nesse caso, a cópia é marcada como LOST e o custo do livro é adicionado ao saldo do cartão. Eventualmente, a cópia pode ser removida do inventário atual de cópias de filiais e armazenada em um arquivo histórico.
Adicionado CHECK CONSTRAINT na tabela Bookcopies para a coluna de condição
ALTER TABLE [dbo].[bookcopies] WITH CHECK ADD CONSTRAINT [CK__bookcopie__condi__09746778]
CHECK (([condition] = ' NEW ' OR [condition] = ' EXCELLENT ' OR [condition] = ' GOOD ' OR [condition] = ' WORN ' OR [condition] = ' POOR ' OR [condition] = ' LOST ' )) Procedimento armazenado para descartar livro em POOR condições
CREATE PROCEDURE [dbo].[USP_DiscardBook]
@copy_id INT
AS
BEGIN
-- Check if copy_id is valid
IF NOT EXISTS( SELECT TOP 1 1 FROM bookcopies WHERE copy_id = @copy_id)
BEGIN
;THROW 50001 , ' Book copy with provided ID does not exist. ' , 1
END
-- Check if book is returned
IF EXISTS( SELECT TOP 1 1 FROM bookcopies WHERE copy_id = @copy_id AND isavailable = 0 )
BEGIN
;THROW 50002 , ' Book copy with provided ID has not been returned. ' , 1
END
-- Check if book has not been discarded
IF EXISTS( SELECT TOP 1 1 FROM bookcopies WHERE copy_id = @copy_id AND isactive = 0 )
BEGIN
;THROW 50003 , ' Book copy with provided ID has been already discarded. ' , 1
END
UPDATE bookcopies SET isavailable = 0 , isactive = 0 , condition = ' POOR ' WHERE copy_id = @copy_id
END Procedimento armazenado para descartar um livro LOST
CREATE PROCEDURE [dbo].[USP_DiscardLostBook]
@copy_id AS INT ,
@card_id AS INT
AS
BEGIN
SET NOCOUNT ON ;
BEGIN TRY
BEGIN TRANSACTION
-- #region Check borrowed book exists
IF NOT EXISTS( SELECT TOP 1 1 FROM books_borrowed WHERE card_id = @card_id AND copy_id = @copy_id AND isReturned = 0 )
BEGIN
;THROW 50001 , ' There is no borrowed book with the given details. ' , 1
END
-- #endregion
DECLARE @id INT = ( SELECT id FROM books_borrowed WHERE card_id = @card_id AND copy_id = @copy_id AND isReturned = 0 )
DECLARE @daysElapsed INT = ( SELECT DATEDIFF(DD,borroweddate,GETDATE()) FROM books_borrowed WHERE id = @id)
-- Set isReturned to true
UPDATE books_borrowed SET isReturned = 1 , returndate = GETDATE() WHERE id = @id
-- Set condition to LOST
UPDATE bookcopies SET condition = ' LOST ' ,isavailable = 0 , isactive = 0 WHERE copy_id = @copy_id
DECLARE @i INT = ( SELECT MAX (id) + 1 FROM bookcopy_history)
-- Insert note to book history table
INSERT INTO bookcopy_history
VALUES
(
ISNULL(@i, 1 ),
@copy_id,
' Book with id: ' + @copy_id + ' has been lost by user with cardid: ' + @card_id,
GETDATE()
)
DECLARE @pr DECIMAL ( 6 , 2 )
IF(@daysElapsed > 14 )
BEGIN
DECLARE @typeId INT = ( SELECT tc . title_type_id FROM bookcopies bc JOIN titlecategory tc ON tc . title_id = bc . title_id WHERE copy_id = @copy_id)
-- Check if Juvenile
IF(@typeId = 4 )
BEGIN
SET @pr = . 05
END
ELSE
BEGIN
SET @pr = . 10
END
-- Update card balancedue
UPDATE borrowers SET balancedue = balancedue + (@pr * @daysElapsed) WHERE card_id = @card_id
END
PRINT( ' Book Has Been Sucessfully discarded as LOST. ' )
COMMIT TRANSACTION
END TRY
BEGIN CATCH
ROLLBACK TRANSACTION
PRINT( ' An Error Occured During The Transaction. Error SP: ' + ERROR_PROCEDURE() + ' Error line: ' + CAST(ERROR_LINE() AS VARCHAR ))
PRINT(ERROR_MESSAGE())
END CATCH
END Existem várias filiais neste sistema de biblioteca de empréstimo. Para cada filial armazene o branch id , name , address , telephone number , fax number , head librarian . Uma filial pode empregar vários bibliotecários, mas apenas um bibliotecário-chefe . Para cada bibliotecário, armazene o employee id , name , address , telephone number , salary e cell phone number . Um bibliotecário pode ser atribuído a apenas uma filial. As filiais têm diferentes tipos de funcionários. Alguns tipos são: Librarian , Network Administrator , Computer Programmer , IT Manager , Floor Manager , Custodian , Accountant , Data Analyst . Os bibliotecários devem ter se formado em biblioteconomia. Para cada funcionário, a biblioteca mantém name , address , phone number , birthdate , hire date e type of employee . Para bibliotecários, a biblioteca também mantém quando o bibliotecário obteve seu diploma e a escola em que o bibliotecário obteve o diploma. A Biblioteca oferece suporte a dois tipos de PayTypes: salaried e hourly . Os empregados assalariados recebem um salário anual que é pago em 12 parcelas no primeiro dia de cada mês . Os funcionários administrativos recebem um salário por hora . Todos os funcionários recebem vacation time dependendo do tempo de serviço . O período mínimo de férias é de duas semanas . A biblioteca mantém um registro de quantas horas cada tipo de funcionário administrativo registrou durante cada semana em que trabalhou . Este registro é usado para produzir paychecks para funcionários administrativos no final de cada semana. Os bibliotecários ganham entre 20.000 e 70.000 por ano. A taxa de pagamento para trabalhadores horistas deve ser de pelo menos 15,00 . Um bibliotecário não pode ser contratado antes de obter o título de MS em Biblioteconomia .
Gatilho para garantir restrições na tabela Employees
CREATE TRIGGER [dbo].[CheckEmployees]
ON [dbo].[employees]
INSTEAD OF INSERT
AS
BEGIN
DECLARE @branchId INT = ( SELECT branch_id FROM inserted)
DECLARE @isHead BIT = ( SELECT ishead_librarian FROM inserted)
DECLARE @empTypeId INT = ( SELECT employee_type_id FROM inserted)
DECLARE @salaryType CHAR ( 1 ) = ( SELECT salary_type FROM inserted)
DECLARE @salary DECIMAL ( 6 , 0 ) = ( SELECT salary FROM inserted)
DECLARE @degreeid INT = ( SELECT degree_id FROM inserted)
-- phone can be used as unique identifier
DECLARE @phone VARCHAR ( 12 ) = ( SELECT cellphone FROM inserted)
IF(@isHead = 1 )
BEGIN
-- Check if head librarian exists for the branch
IF EXISTS( SELECT TOP 1 1 FROM employees WHERE branch_id = @branchId AND ishead_librarian = 1 )
BEGIN
RAISERROR( ' There is already a head librarian on this branch ' , 10 , 1 )
ROLLBACK
END
-- Check if employee is of type librarian
IF(@empTypeId <> 1 )
BEGIN
RAISERROR( ' Only librarians can be head librarian ' , 10 , 1 )
ROLLBACK
END
END
-- Check if librarian exists
IF EXISTS( SELECT TOP 1 1 FROM employees WHERE cellphone = @phone AND isActive = 1 )
BEGIN
RAISERROR( ' Employee is already assigned to ' , 10 , 1 )
ROLLBACK
END
-- Check if librarian exists
IF(@salaryType = ' C ' AND @salary < 15 )
BEGIN
RAISERROR( ' Minimum hourly pay for clerical employees must be greater than 15 dollars. ' , 10 , 1 )
ROLLBACK
END
IF(@empTypeId = 1 AND (@salary < 20000 OR @salary > 70000 ))
BEGIN
RAISERROR( ' Salary for librarians must be between 20000 and 70000 ' , 10 , 1 )
ROLLBACK
END
IF(@empTypeId = 1 AND @degreeid <> 2 )
BEGIN
RAISERROR( ' Librarian must have earned MS degree in Library Sciences. ' , 10 , 1 )
ROLLBACK
END
PRINT( ' Employee has been sucessfully added. ' )
END
GO
ALTER TABLE [dbo].[employees] ENABLE TRIGGER [CheckEmployees]
Procedimento armazenado para atualização anual Vacation Hours dos funcionários
CREATE PROCEDURE [dbo].[USP_UpdateEmployeeVacationHours]
AS
BEGIN
UPDATE employees
SET vacation_hours = CASE
WHEN DATEDIFF(YY,hiredate,GETDATE()) BETWEEN 0 AND 5 THEN 114
WHEN DATEDIFF(YY,hiredate,GETDATE()) BETWEEN 5 AND 10 THEN 154
ELSE 200
END
FROM employees
ENDListe o título do livro que é o livro mais popular a ser emprestado. (Ou seja, foi emprestado com mais frequência várias vezes)
SELECT t . title
, COUNT (id) AS [Borrowed Count]
FROM books_borrowed bb
JOIN bookcopies bc ON bc . copy_id = bb . copy_id
JOIN titles t ON t . title_id = bc . title_id
GROUP BY t . title
HAVING COUNT (id) >= ALL
(
SELECT COUNT (id) AS [Borrowed Count]
FROM books_borrowed bb
JOIN bookcopies bc ON bc . copy_id = bb . copy_id
JOIN titles t ON t . title_id = bc . title_id
GROUP BY t . title
)Livros emprestados com contagem total
SELECT t . title
, COUNT (id) AS [Borrowed Count]
FROM books_borrowed bb
JOIN bookcopies bc ON bc . copy_id = bb . copy_id
JOIN titles t ON t . title_id = bc . title_id
GROUP BY t . title
ORDER BY [Borrowed Count] DESCQual bibliotecário tem o terceiro salário mais alto atualmente?
SELECT *
FROM
(
SELECT e . employee_id
,first_name + ' ' + last_name AS [Full Name]
,salary
,ROW_NUMBER() OVER( ORDER BY salary DESC ) AS RowNo
FROM employees e
WHERE isActive = 1 AND e . employee_type_id =
(
SELECT et . id
FROM employee_type et
WHERE [type] = ' Librarian '
)
) subQ
WHERE subQ . RowNo = 3Para cada funcionário, liste seu nome e o nome da filial para a qual trabalha atualmente e quantos funcionários trabalham para essa filial.
SELECT e . employee_id
, e . first_name + ' ' + e . last_name AS [Fullname]
, b . name
, COUNT ( e . employee_id ) OVER (PARTITION BY b . branch_id ) AS [Branch Employee Count]
FROM employees e
JOIN branchs b ON e . branch_id = b . branch_id
ORDER BY [Branch Employee Count] DESCPara cada livro, liste o título e a editora do livro e o número de exemplares atualmente estocados desse título em cada filial, independentemente de ele estar atualmente emprestado.
SELECT t . title
, t . title_id
, p . pub_name
, bc . branch_id
, COUNT ( bc . title_id ) AS [Copy Count]
FROM titles t
JOIN publishers p ON t . pub_id = p . pub_id
JOIN bookcopies bc ON bc . title_id = t . title_id
GROUP BY t . title
, t . title_id
, p . pub_name
, bc . branch_idPara cada trimestre do ano corrente, liste para cada filial a quantidade total de livros que foram emprestados naquele trimestre. O primeiro trimestre corresponde aos meses de janeiro, fevereiro, março. O segundo trimestre corresponde aos meses de abril, maio, junho etc. Liste os valores de cada um desses trimestres, na mesma linha.
SELECT b . name
,(
SELECT COUNT ( bb . copy_id ) AS [Total]
FROM bookcopies bc
JOIN books_borrowed bb ON bb . copy_id = bc . copy_id
WHERE MONTH( bb . borroweddate ) IN ( 1 , 2 , 3 ) AND b . branch_id = bc . branch_id
) AS [Count Of First Quarter]
,(
SELECT COUNT ( bb . copy_id ) AS [Total]
FROM bookcopies bc
JOIN books_borrowed bb ON bb . copy_id = bc . copy_id
WHERE MONTH( bb . borroweddate ) IN ( 4 , 5 , 6 ) AND b . branch_id = bc . branch_id
) AS [Count Of Second Quarter]
,(
SELECT COUNT ( bb . copy_id ) AS [Total]
FROM bookcopies bc
JOIN books_borrowed bb ON bb . copy_id = bc . copy_id
WHERE MONTH( bb . borroweddate ) IN ( 7 , 8 , 9 ) AND b . branch_id = bc . branch_id
) AS [Count Of Third Quarter]
,(
SELECT COUNT ( bb . copy_id ) AS [Total]
FROM bookcopies bc
JOIN books_borrowed bb ON bb . copy_id = bc . copy_id
WHERE MONTH( bb . borroweddate ) IN ( 10 , 11 , 12 ) AND b . branch_id = bc . branch_id
) AS [Count Of Fourth Quarter]
FROM branchs bPara cada cartão, liste o nome do mutuário e o nome dos livros que ele emprestou atualmente no cartão, que ainda não foram devolvidos
SELECT b . first_name + ' ' + b . last_name AS [Borrower Fullname]
, t . title
FROM borrowers b
JOIN books_borrowed bb ON b . card_id = bb . card_id
JOIN bookcopies bc ON bc . copy_id = bb . copy_id
JOIN titles t ON t . title_id = bc . title_id
WHERE bb . isReturned = 0
ORDER BY [Borrower Fullname]Para cada cartão, liste o nome do mutuário e na mesma linha a quantidade de livros emprestados em 2020 e a quantidade de livros emprestados em 2021 com esse cartão.
SELECT b . first_name + ' ' + b . last_name AS [Borrower Fullname]
,(
SELECT COUNT ( bb . id )
FROM books_borrowed bb
WHERE YEAR( bb . borroweddate ) = 2020 AND b . card_id = bb . card_id
) AS [Borrowed2020]
,(
SELECT COUNT ( bb . id )
FROM books_borrowed bb
WHERE YEAR( bb . borroweddate ) = 2021 AND b . card_id = bb . card_id
) AS [Borrowed2021]
,(
SELECT COUNT ( bb . id )
FROM books_borrowed bb
WHERE YEAR( bb . borroweddate ) = 2022 AND b . card_id = bb . card_id
) AS [Borrowed2022]
FROM borrowers b Para um cartão específico, liste quais outros cartões emprestaram TODOS os mesmos livros que foram emprestados usando este cartão. (dividir consulta). Você escolhe o cartão que irá combinar.
SELECT AllBooks . card_id
FROM
(
SELECT DISTINCT bb . card_id
,title
FROM books_borrowed bb
JOIN bookcopies bc ON bc . copy_id = bb . copy_id
JOIN titles t ON t . title_id = bc . title_id
) AS AllBooks
JOIN
(
SELECT DISTINCT bb . card_id
,title
FROM books_borrowed bb
JOIN bookcopies bc ON bc . copy_id = bb . copy_id
JOIN titles t ON t . title_id = bc . title_id
WHERE bb . card_id = 2
) AS Card1Books ON Card1Books . title = AllBooks . title
GROUP BY AllBooks . card_id
HAVING COUNT ( AllBooks . title ) = (
SELECT COUNT (title)
FROM books_borrowed bb
JOIN bookcopies bc ON bc . copy_id = bb . copy_id
JOIN titles t ON t . title_id = bc . title_id
WHERE bb . card_id = 2
)Liste o nome do funcionário que trabalha na biblioteca há mais tempo
SELECT e . first_name + ' ' + e . last_name AS [Employee Fullname]
, e . hiredate
,DATEDIFF(YY, e . hiredate ,GETDATE()) AS [Years of Employment]
FROM employees e
WHERE e . hiredate = ( SELECT MIN (hiredate) FROM employees)Para cada livro, liste o título e a filial em que ele se encontra, se não estiver emprestado no momento
SELECT t . title
, b . name
FROM titles t
JOIN bookcopies bc ON t . title_id = bc . title_id
LEFT JOIN books_borrowed bb ON bb . copy_id = bc . copy_id
JOIN branchs b ON b . branch_id = bc . branch_id
WHERE bc . isactive = 1 AND isavailable = 1Liste os nomes dos mutuários e a identificação do cartão que eles possuem, caso ainda não tenha expirado.
SELECT b . first_name + ' ' + b . last_name AS [Borrower]
, b . card_id
FROM borrowers b
WHERE isexpired = 0Para cada autor, liste seu nome e os títulos dos livros que escreveu
SELECT DISTINCT a . au_fname + ' ' + a . au_lname AS [Author]
, t . title
FROM authors a
JOIN titleauthor ta On ta . au_id = a . au_id
JOIN titles t ON t . title_id = ta . title_idPara cada autor, liste seu nome e o nome das categorias de livros que ele escreveu
SELECT DISTINCT a . au_fname + ' ' + a . au_lname AS [Author]
,c.[type]
FROM authors a
JOIN titleauthor ta On ta . au_id = a . au_id
JOIN titles t ON t . title_id = ta . title_id
JOIN titlecategory tc ON tc . title_id = t . title_id
JOIN category c ON c . type_id = tc . title_type_idPara cada funcionário, calcule a quantidade de dinheiro que ele deveria ter ganho este ano com base nas horas registradas.
SELECT subQ . employee_id
,subQ.[Hours Total] * e . salary
FROM
(
SELECT e . employee_id
, SUM (sl.[hours]) AS [Hours Total]
FROM employees e
JOIN shift_logs sl ON e . employee_id = sl . employee_id
WHERE YEAR( sl . shiftdate ) = YEAR(GETDATE()) AND e . salary_type = ' C '
GROUP BY e . employee_id
) subQ
JOIN employees e ON e . employee_id = subQ . employee_idListe o título dos livros que nunca foram emprestados.
SELECT t . title
FROM titles t
WHERE t . title_id NOT IN
(
SELECT DISTINCT t . title_id
FROM borrowers b
JOIN books_borrowed bb ON b . card_id = bb . card_id
JOIN bookcopies bc ON bc . copy_id = bb . copy_id
JOIN titles t ON t . title_id = bc . title_id
)Para cada filial, liste a quantidade total de livros, quantidade total por categoria, quantidade total por autor
SELECT b . name
,(
SELECT COUNT ( bc . copy_id )
FROM bookcopies bc
WHERE bc . branch_id = b . branch_id
) AS [Book Count]
,(
SELECT COUNT (DISTINCT tc . title_type_id )
FROM bookcopies bc
JOIN titles t ON t . title_id = bc . title_id
JOIN titlecategory tc ON tc . title_id = t . title_id
WHERE bc . branch_id = b . branch_id
) AS [Category Count]
,(
SELECT COUNT (DISTINCT ta . au_id )
FROM bookcopies bc
JOIN titles t ON t . title_id = bc . title_id
JOIN titleauthor ta On t . title_id = ta . title_id
WHERE bc . branch_id = b . branch_id
) AS [Category Count]
FROM branchs b Para cada cartão, liste o nome do titular do cartão, liste a categoria dos livros e cada livro que foi emprestado neste cartão. Na mesma lista de consulta, quantos livros foram emprestados para cada categoria e quantos livros foram emprestados no total com este cartão.
WITH CTE
AS
(
SELECT b . first_name + ' ' + b . last_name AS [Borrower]
, t . title
,c.[type]
FROM borrowers b
JOIN books_borrowed bb ON b . card_id = bb . card_id
JOIN bookcopies bc ON bc . copy_id = bb . copy_id
JOIN titles t ON t . title_id = bc . title_id
JOIN titlecategory tc ON tc . title_id = t . title_id
JOIN category c ON c . type_id = tc . title_type_id
)
SELECT Borrower
,title
,[type]
, COUNT ( c . title ) OVER (PARTITION BY Borrower,TYPE) AS [Category Count]
, COUNT ( c . title ) [Total Books Borrowed]
FROM CTE c
GROUP BY Borrower
,title
,[type]
ORDER BY [Borrower]Em uma linha, liste quantos funcionários estão empregados atualmente para cada tipo de funcionário.
SELECT et.[type]
, COUNT ( e . employee_id ) AS [Employee Count]
FROM employees e
JOIN employee_type et ON e . employee_type_id = et . id
WHERE e . isActive = 1
GROUP BY et.[type]
ORDER BY [Employee Count] DESC Qual é o nome do mutuário que atualmente emprestou mais livros.
SELECT b . first_name + ' ' + b . last_name AS [Borrower]
FROM borrowers b
JOIN books_borrowed bb ON bb . card_id = b . card_id
GROUP BY b . first_name + ' ' + b . last_name
HAVING COUNT ( bb . copy_id ) >= ALL
(
SELECT COUNT (copy_id)
FROM books_borrowed
GROUP BY card_id
) Liste os nomes dos mutuários que emprestaram o livro A e o livro B (você pode escolher os títulos dos livros específicos).
SELECT DISTINCT b . first_name + ' ' + b . last_name AS [Borrower]
FROM titles t
JOIN bookcopies bc ON t . title_id = bc . title_id
JOIN books_borrowed bb ON bb . copy_id = bc . copy_id
JOIN borrowers b ON b . card_id = bb . card_id
WHERE t . title_id = ' UX2157 '
INTERSECT
SELECT DISTINCT b . first_name + ' ' + b . last_name AS [Borrower]
FROM titles t
JOIN bookcopies bc ON t . title_id = bc . title_id
JOIN books_borrowed bb ON bb . copy_id = bc . copy_id
JOIN borrowers b ON b . card_id = bb . card_id
WHERE t . title_id = ' BR5671 ' Link para todo o arquivo de scripts do Pubs DB: Ver arquivo
Link para todo o arquivo bak do Pubs DB: Ver arquivo
Aplicativo de interface de usuário front-end simples para o aplicativo Pubs Database View
Nury Amanmadov - @amanmadov - [email protected]
Link do projeto: https://github.com/amanmadov/msin616-final-project
(voltar ao topo)
