Using regular expressions to extract the contents of ( ) in java

Author：Eve Cole Update Time：2024-11-19 15:24:01

I encountered a small problem yesterday. I needed to process some users in batches. The format of the users sent from the front desk was as follows. I wanted to extract the content between the brackets (without brackets).

Teacher 10(0010)
Teacher 11(0011)
Teacher 9(009)
Teacher 12(0012)
Teacher 13(0013)
Teacher 14(0014)

I originally wanted to use Java's String.split() and substring() to do it, but it was troublesome to process it multiple times, so I used regular expressions. Although I have almost forgotten the syntax, I think it is more convenient to use assertions (the key is to hope that the results do not have parentheses). Open RegexBuddy and give it a try, and it’s easy to do:

The following is the java implementation code:

Copy the code code as follows:

public List<String> getTeacherList(String managers){
List<String> ls=new ArrayList<String>();
Pattern pattern = Pattern.compile("(?<=//()(.+?)(?=//))");
Matcher matcher = pattern.matcher(managers);
while(matcher.find())
ls.add(matcher.group());
return ls;
}

Finally, here are the zero-width assertions used:

wide assertion	(?=exp)	Match the position before exp
	(?<=exp)	Match the position after exp
	(?!exp)	Matches a position that is not followed by exp
	(?<!exp)	Match the position that is not preceded by exp