Perform PHP syntax highlighting on the test file ("test.php"):
<html><body><?phpshow_source("test.php");?></body></html>The browser output for the above code is as follows (depending on what is in the file):
<html><body> <?php echo ( "test.php" ); ?> </body></html>The HTML output of the above code is as follows (view source code):
<html><body><code><span style="color: #000000"><html><br /><body><br /><span style="color: #0000BB"><? php<br /></span><span style="color: #007700">echo (</span><span style="color: #DD0000">"test.php"</span><span style="color: #007700">);<br /></span><span style="color: #0000BB">?><br /></span></body><br /></html></span></code></body></html>The show_source() function performs PHP syntax highlighting on files. Syntax highlighting is done using HTML tags.
The color used for highlighting can be set through the php.ini file or by calling the ini_set() function.
show_source() is an alias for highlight_file().
Note: When using this function, the entire file will be displayed, including passwords and other sensitive information!
show_source( filename,return )
| parameter | describe |
|---|---|
| filename | Required. Specifies the files to be displayed. |
| return | Optional. If this parameter is set to TRUE, the function returns the highlighted code as a string instead of outputting it directly. The default is FALSE. |
| Return value: | If the return parameter is set to TRUE, the function will return the highlighted code as a string instead of outputting it directly. Otherwise, TRUE is returned on success and FALSE on failure. |
|---|---|
| PHP version: | 4+ |
| Update log: | As of PHP 4.2.1, this function is now also affected by safe_mode and open_basedir. However, safe_mode was removed in PHP 5.4. The return parameter was added in PHP 4.2.0. |