ASP function to detect whether the link is normal

<%
Function urlChk(sUrl)
on error resume next
Set xmlHttp = Server.CreateObject("Microsoft.XMLHTTP")
xmlHttp.open "GET",sUrl,false
xmlHttp.send
    if xmlHttp.Status <> 200 then
        urlChk=false
    else
        urlChk=true
    end if
End Function

sUrl="http://code.dlstu.cn"

if urlChk(sUrl) then
    response.write(sUrl&"(可以正常访问！)")
else
    response.write(sUrl&"(页面打开错误！)")
end if
%>