ajaxSubmit插件jQuery1.4.2版JSON问题

作者：Eve Cole 更新时间：2010-09-09 10:42:32

jQuery Form 插件基于jQuery v1.4.2版返回JSON数据时一直报错；修改以下内容可恢复；

原后台输出数据格式如：{sitename:'开发者网络',siteurl:'www.AAA.net',level:10} 需改为 {"sitename":"开发者网络","siteurl":"www.AAA.net","level":10}

也就是在名称需以双引号包括；因为 jQuery 1.4.2版在 parseJSON 方法中添加了正则判断

if ( /^[],:{}s]*$/.test(data.replace(/\(?:["\/bfnrt]|u[0-9a-fA-F]{4})/g, "@")
.replace(/"[^"\nr]*"|true|false|null|-?d+(?:.d*)?(?:[eE][+-]?d+)?/g, "]")
.replace(/(?:^|:|,)(?:s*[)+/g, "")) ) {

   // Try to use the native JSON parser first
   return window.JSON && window.JSON.parse ?
    window.JSON.parse( data ) :
    (new Function("return " + data))();

  } else {
   jQuery.error( "Invalid JSON: " + data );
  }

jQuery Form 插件需要修改的地方

if (scr || s.textarea) {
     // see if user embedded response in textarea
     var ta = doc.getElementsByTagName('textarea')[0];
     if (ta) {
      xhr.responseText = ta.value;
     }
     else if (scr) {
      // account for browsers injecting pre around json response
      var pre = doc.getElementsByTagName('pre')[0];
      if (pre) {
       xhr.responseText = pre.innerHTML;
      }
     }
    }
    else if (s.dataType == 'xml' && !xhr.responseXML && xhr.responseText != null) {
     xhr.responseXML = toXml(xhr.responseText);
    }

修改为：

if (scr || s.textarea) {
     // see if user embedded response in textarea
     var ta = doc.getElementsByTagName('textarea')[0];
     if (ta) {
      xhr.responseText = ta.value;
     }
     else if (scr) {
      // account for browsers injecting pre around json response
      var pre = doc.getElementsByTagName('pre')[0];
      if (pre) {
       xhr.responseText = pre.innerHTML;
      }else xhr.responseText=doc.body.innerHTML;
     }
    }
    else if (s.dataType == 'xml' && !xhr.responseXML && xhr.responseText != null) {
     xhr.responseXML = toXml(xhr.responseText);
    }

原文地址：http://www.vifo.net/Program/JavaScript/10090191.shtml