Friends who have a certain understanding of color ranges and optional color commands know that generally, the color at any point in the image contains two colors: one is the color corresponding to MAX (R, G, B), in order For the convenience of discussion, we call it monochrome; the other is the color defined by MAX(R,G,B) and MID(R,G,B). Also for the convenience of discussion, we call it Recolor.
When MAX(R,G,B)=MID(R,G,B)<>MIN(R,G,B), there are only complex colors but no single colors;
When MID(R,G,B)=MIN(R,G,B)<>MAX(R,G,B), there is only single color but no complex color;
When MAX(R,G,B)=MID(R,G,B)=MIN(R,G,B), it is colorless and neutral gray.
The diagram for preparing the experiment is as follows:
When each slider is 0:
Only when the single color slider is not 0
Only when the complex color slider is not 0
Situation when each slider is not 0:
Drag directly within the image to convert to black and white
This command has a special feature. Not only can you drag the slider in the dialog box to convert, you can also directly drag the corresponding area in the image to convert.
As mentioned before, under normal circumstances, the color at any point in the image includes two colors: single color and complex color. So, when dragging directly in the image, does it change the single color or the complex color? After experiments, it is judged according to the following rules:
When MID(R,G,B)>MIN(R,G,B)+[MAX(R,G,B),-MIN(R,G,B)]/2, drag and change directly in the image The one that changes is a complex color, and the other way around is a single color.
When the "Dyeing" option is checked
First do the following experiment:
After checking the tint option, adjust the hue and saturation sliders in the dialog box. Then click the color patch on the right to pop up the color picker, write down the H, S, and B values of the color patch, and also note down the R, G, and B values of the sampling point in the information palette.
Simulate staining options with blending modes
Uncheck the "Stain" option, then create a new layer on top of it and fill it with the H, S, and B values you just noted down, and change the layer's blending mode to "Color". Observe the RGB value of the sampling point in the information palette, which is exactly the same as the RGB value after checking the "Stain" option in the previous step.
think
The principle of the black and white conversion command has now been revealed. But there is another question worth thinking about: in the case of dyeing, the color being dyed is obviously related to the lightness. Why are there only "Hue" and "Saturation" sliders in the "Dyeing" option, but not the "Brightness" slider? Woolen cloth?
My understanding is that everyone's habitual thinking should be that the adjusted black and white image constitutes the brightness of the image, which together with the "hue" and "saturation" in the dyeing frame constitute the final color. If you add a brightness slider to the coloring box, there will be two brightnesses, which can easily cause confusion. Therefore, PS adopted the trick of concealing the truth here and omitted the "brightness" slider that should have been there.
In addition, friends who understand color mixing modes should also know that the "brightness" in the dyeing frame and the "brightness" in the color mixing mode are not the same thing at all, and naturally they are not contradictory. Please correct me.