PHP is_resource() function

The is_resource() function is used to detect whether the variable is a resource type.

PHP version requirements: PHP 4, PHP 5, PHP 7

grammar

 bool is_resource (mixed $var)

Parameter description:

$var: The variable to be tested.

return value

If the specified variable is of resource type, is_resource() returns TRUE, otherwise it returns FALSE.

Example

In the following example, you need to create the demo.txt file in the current directory.

Example

The output is:

 File opened successfully...